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| "kastnna" <kastnna[at]auburnalum.org> wrote in message news:1170442464.350469.250770[at]v45g2000cwv.googlegroups.com... - quote - > Wouldn't 5% compounded growth be 100, 105, 110.25 (not 105.25), > 115.76, etc? Yes, I was in error. Thanks for catching that. -- Joe |
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| Bill/Dave thanks so much for the help. That's exactly what I needed. -- Joe |
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| On Feb 2, 12:25 pm, "Joe D." <nos...[at]invalid.invalid> wrote: - quote - > I'm trying to find the formula to calculate the final value of a
Assuming that the initial balance in the account is I, that deposits> non-interest-bearing account, given annual deposits which increase at x% > compounded rate. Would appreciate any help. > Inputs: > - # of years > - initial account value > - initial annual deposit amount > - % annual compounded increase of annual deposit > E.g, initial account value is $1000, it's non-interest bearing so stays > constant except for deposits. > Initial annual deposit is $100, which increases at a 5% compounded annual > rate (next year's deposit would be $105, the following would be $105.25, > etc). > This continues for, say, 90 years what's the account final value? Just > looking for the formula. of amount D are made on the last day of the year, the balance on the last day of the Nth year is D [(1+r)^N - 1] B = ------------------------ + I - D r Examples: With initial balance $1000 and deposits of $100 growing at a 5% compounded annual rate: After 1 year, you would have B = 100*(1.05^2-1)/.05 + 1000 - 100 = $1,105 After 90 years, you would have B = 100*(1.05^90 - 1)/.05 + 1000 - 100 = $160,360.73 Hope this helps. Dave |
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| - quote - > - # of years
This is the same thing as the annuity formula in reverse. Instead of> - initial account value > - initial annual deposit amount > - % annual compounded increase of annual deposit adding interest to older deposits, you're making newer deposits larger. Conceptually, you've reversed the order of the summation, but that doesn't matter. Let T be the number of years, D be the initial annual deposit and r be the rate at which the deposits increase and F be the future value. Then you want: F = D + D(1+r) + D(1+r)^2 + ... + D(1+r)^(T-1) F = D(1 + (1+r) + (1+r)^2 + ... + (1+r)^(T-1)) F = D * (1 - (1+r)^T) / (1 - (1+r)) F = D * (1 - (1+r)^T) / -r F = D * ((1+r)^T - 1) / r Since the initial account balance isn't earning interest, you can just add it to the formula above. --Bill |
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| - quote - > E.g, initial account value is $1000, it's non-interest bearing so stays > constant except for deposits. > Initial annual deposit is $100, which increases at a 5% compounded annual > rate (next year's deposit would be $105, the following would be $105.25, > etc). > This continues for, say, 90 years what's the account final value? Just > looking for the formula. Wouldn't 5% compounded growth be 100, 105, 110.25 (not 105.25), 115.76, etc? |
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| I'm trying to find the formula to calculate the final value of a non-interest-bearing account, given annual deposits which increase at x% compounded rate. Would appreciate any help. Inputs: - # of years - initial account value - initial annual deposit amount - % annual compounded increase of annual deposit E.g, initial account value is $1000, it's non-interest bearing so stays constant except for deposits. Initial annual deposit is $100, which increases at a 5% compounded annual rate (next year's deposit would be $105, the following would be $105.25, etc). This continues for, say, 90 years what's the account final value? Just looking for the formula. |
| Tags |
| account, annual, compounded, contributions, formula, increase, noninterestbearing, rate |
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